SAT question 07f2829b (Distributions, Center & Spread)

Question

The table above shows the number of international tourist arrivals, rounded to the nearest tenth of a million, to the top nine tourist destinations in both 2012 and 2013 . Based on the information given in the table, how much greater, in millions, was the median number of international tourist arrivals to the top nine tourist destinations in 2013 than the median number in 2012 , to the nearest tenth of a million?

College Board · Accepted Answer

The correct answer is 13/10,1.3,1.30. The correct answer is (13)/(10) . The median number of tourists is found by ordering the number of tourists from least to greatest and determining the middle value from this list. When the number of tourists in 2012 is ordered from least to greatest, the middle value, or the fifth number, is 46.4 million. When the number of tourists in 2013 is ordered from least to greatest, the middle value, or the fifth number, is 47.7 million. The difference between these two medians is 47.7 - 46.4 = 1.3 million. Note that 13/10, 1.3, and 1.30 are examples of ways to enter a correct answer.

Country	2012	2013
France	$83.0$	$84.7$
United States	$66.7$	$69.8$
Spain	$57.5$	$60.7$
China	$57.7$	$55.7$
Italy	$46.4$	$47.7$
Turkey	$35.7$	$37.8$
Germany	$30.4$	$31.5$
United Kingdom	$26.3$	$32.2$
Russia	$24.7$	$28.4$

Explanation

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Student discussion

SAT Question 07f2829b: Distributions, Center & Spread answer and explanation with Desmos solution

Explanation

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Student discussion