SAT Question 09f58996: Nonlinear Functions answer and explanation with Desmos solution

The value of $f\left(36\right)$ is the value of $f\left(x\right)$ when $x=36$. Substituting $36$ for $x$ in the given equation yields $f\left(36\right)=6+\sqrt{36}$, which is equivalent to $f\left(36\right)=6+6$, or $f\left(36\right)=12$. Thus, the value of $f\left(36\right)$ is $12$.