SAT Question 208626df: Linear Inequalities answer and explanation with Desmos solution

Choice B is correct. It’s given that a rectangle has length $l$ and width $w$, and the inequality $2l+2w\le 27$ gives the possible values of $l$ and $w$ for which the perimeter of this rectangle is less than or equal to $27$. To determine the best interpretation of $(l,w)=(8,3)$ in this context, the values can be substituted in the given inequality. Substituting $8$ for $l$ and $3$ for $w$ in this inequality yields $2(8)+2(3)\le 27$, which is equivalent to $16+6\le 27$, or $22\le 27$. Since this inequality is true, if the rectangle has length $8$ and width $3$, its perimeter is less than or equal to $27$.