SAT Question 3de7a7d7: Nonlinear Equations In One Variable And Systems Of Equations In Two Variables answer and explanation with Desmos solution

Choice B is correct. Subtracting $x^2$ from both sides of the given equation yields $x^2-4=0$. Adding $4$ to both sides of the equation gives $x^2=4$. Taking the square root of both sides of the equation gives $x=2$ or $x=-2$. Therefore, $x=2$ is one solution to the original equation. Alternative approach: Subtracting $x^2$ from both sides of the given equation yields $x^2-4=0$. Factoring this equation gives $x^2-4=(x+2)(x-2)=0$, such that $x=2$ or $x=-2$. Therefore, $x=2$ is one solution to the original equation.