SAT Question 4b6f0a3f: Nonlinear Equations In One Variable And Systems Of Equations In Two Variables answer and explanation with Desmos solution

The given quadratic equation can be rewritten in factored form as $(x-8)(x+3)=0$. Based on the zero product property, it follows that $x-8=0$ or $x+3=0$. Adding $8$ to both sides of the equation $x-8=0$ yields $x=8$. Subtracting $3$ from both sides of the equation $x+3=0$ yields $x=-3$. Therefore, the solutions to the given equation are $8$ and $-3$. It follows that the sum of the solutions to the given equation is $8+(-3)$, or $5$.