SAT Question 4b7bb316: Area and Volume answer and explanation with Desmos solution

The exterior surface area of a figure is the sum of the areas of all its faces. It's given that the box does not have a lid and that each side of the box is in the shape of a square. Therefore, the box consists of $5$ congruent square faces. It's also given that the length of each edge is $29$ inches. Let $s$ represent the length of an edge of a square. It follows that the area of a square is equal to $s^2$. Therefore, the area of each of the $5$ square faces is equal to $29^2$, or $841$, square inches. Since the box consists of $5$ congruent square faces, it follows that the sum of the areas of all its faces, or the exterior surface area of this box without a lid, is $5\left(841\right)$, or $4,205$, square inches.