SAT Question 899c6042: Area and Volume answer and explanation with Desmos solution

It's given that the right circular cone has a height of $22$ centimeters (cm) and a base with a diameter of $6$ cm. Since the diameter of the base of the cone is $6$ cm, the radius of the base is $3$ cm. The volume $V$, ${\text{in cm}}^3$, of a right circular cone can be found using the formula $V=\frac{1}{3}\pi r^{2}h$, where $h$ is the height, $\text{in cm}$, and $r$ is the radius, $\text{in cm}$, of the base of the cone. Substituting $22$ for $h$ and $3$ for $r$ in this formula yields $V=\frac{1}{3}\pi {\left(3\right)}^2\left(22\right)$, or $V=66\pi$. Therefore, the volume of the cone is $66\pi {\text{cm}}^3$. It's given that the volume of the cone is $n\pi {\text{cm}}^3$. Therefore, the value of $n$ is $66$.