SAT Question 9f934297: Area and Volume answer and explanation with Desmos solution

The surface area of a prism is the sum of the areas of all its faces. A right rectangular prism consists of six rectangular faces, where opposite faces are congruent. It's given that this prism has a length of $28$ cm, a width of $15$ cm, and a height of $16$ cm. Thus, for this prism, there are two faces with area $\left(28\right)\left(15\right){\text{cm}}^2$, two faces with area $\left(28\right)\left(16\right){\text{cm}}^2$, and two faces with area $\left(15\right)\left(16\right){\text{cm}}^2$. Therefore, the surface area, ${\text{in cm}}^2$, of the right rectangular prism is $2\left(28\right)\left(15\right)+2\left(28\right)\left(16\right)+2\left(15\right)\left(16\right)$, or $2,216$.