SAT Question acd30391: Circles answer and explanation with Desmos solution

Choice A is incorrect. The distance between $(-7,3)$ and $(-3,1)$ is $\sqrt{(-7+3{)}^2+(3-1{)}^2}=\sqrt{(-4{)}^2+(2{)}^2}=\sqrt{20}$, which is less than $5$, and therefore $(-7,3)$ lies in the interior of the circle.

Choice B is incorrect because it is the center of the circle.

Choice C is incorrect because the distance between $(0,0)$ and $(-3,1)$ is $\sqrt{(0+3{)}^2+(0-1{)}^2}=\sqrt{(3{)}^2+(1{)}^2}=\sqrt{10}$, which is less than $5$, and therefore $(0,0)$ lies in the interior of the circle.