SAT Question bcb66188: Right Triangles And Trigonometry answer and explanation with Desmos solution

Choice B is correct. If two triangles are similar, then their corresponding angles are congruent. It's given that right triangle $FGH$ is similar to right triangle $JKL$ and angle $F$ corresponds to angle $J$. It follows that angle $F$ is congruent to angle $J$ and, therefore, the measure of angle $F$ is equal to the measure of angle $J$. The sine ratios of angles of equal measure are equal. Since the measure of angle $F$ is equal to the measure of angle $J$, $\sin \left(F\right)=\sin \left(J\right)$. It's given that $\sin \left(F\right)=\frac{308}{317}$. Therefore, $\sin \left(J\right)$ is $\frac{308}{317}$.