SAT Question ee2f611f: Linear Inequalities answer and explanation with Desmos solution

The minimum number of individual trips for which the cost of the monthly pass is less than the cost of individual tickets can be found by assuming the maximum cost of the individual tickets, $$3.50$. If $n$ tickets costing $$3.50$ each are purchased in one month, the inequality $95<3.50n$ represents this situation. Dividing both sides of the inequality by $3.50$ yields $27.14<n$, which is equivalent to $n>27.14$. Since only a whole number of tickets can be purchased, it follows that $28$ is the minimum number of trips.