SAT Question f25a34aa: Nonlinear Functions answer and explanation with Desmos solution

The area of a triangle is equal to one half of the product of the length of the base of the triangle and the height of the triangle. It's given that the length of the base of the triangle is $2x+22$ centimeters and the height of the triangle is $x-10$ centimeters; therefore, its area is $\frac{1}{2}(2x+22)(x-10)$ square centimeters. It's also given that the area of the triangle is equal to $x^2$ square centimeters. Therefore, it follows that $\frac{1}{2}(2x+22)(x-10)=x^2$. This equation can be rewritten as $(x+11)(x-10)=x^2$, or $x^2+x-110=x^2$. Subtracting $x^2$ from both sides of this equation yields $x-110=0$. Adding $110$ to both sides of this equation yields $x=110$. Therefore, the value of $x$ is $110$.