SAT Question fecc446d: Lines, Angles, and Triangles answer and explanation with Desmos solution

Choice A is correct. It's given that a line intersects two parallel lines, forming four acute angles and four obtuse angles. Since there are two parallel lines intersected by a transversal, all four acute angles have the same measure and all four obtuse angles have the same measure. Additionally, each acute angle is supplementary to each obtuse angle. It's given that the measure of one of these eight angles is $(7x-250{)}^{\circ }$. It follows that a supplementary angle has measure $(180-(7x-250){)}^{\circ }$, or $(-7x+430{)}^{\circ }$. It's also given that the sum of the measures of four of the eight angles is $k^{\circ }$. It follows that the possible values of $k$ are $4(7x-250)$; $(7x-250)+3(-7x+430)$; $2(7x-250)+2(-7x+430)$; $3(7x-250)+(-7x+430)$; and $4(-7x+430)$. These values are equivalent to $28x-1,000$; $-14x+1,040$; $360$; $14x-320$; and $-28x+1,720$, respectively. It follows that of the given choices, only $-14x+1,540$ could NOT be equivalent to $k$, for all values of $x$.