SAT Question 6ecdbcb4: Nonlinear Functions answer and explanation with Desmos solution

Choice B is correct. It's given that $f\left(x\right)=(x+6)(x+5)(x-4)$ and $y=f(x)-3$. Substituting $(x+6)(x+5)(x-4)$ for $f\left(x\right)$ in the equation $y=f(x)-3$ yields $y=(x+6)(x+5)(x-4)-3$. Substituting $-6$ for $x$ in this equation yields $y=(-6+6)(-6+5)(-6-4)-3$, or $y=-3$. Substituting $-5$ for $x$ in the equation $y=(x+6)(x+5)(x-4)-3$ yields $y=(-5+6)(-5+5)(-5-4)-3$, or $y=-3$. Substituting $4$ for $x$ in the equation $y=(x+6)(x+5)(x-4)-3$ yields $y=(4+6)(4+5)(4-4)-3$, or $y=-3$. Therefore, when $x=-6$ then $y=-3$, when $x=-5$ then $y=-3$, and when $x=4$ then $y=-3$. Thus, the table of values in choice B represents $y=f(x)-3$.