SAT Question 70753f99: Nonlinear Functions answer and explanation with Desmos solution

Choice B is correct. The graph of a quadratic function in the $xy$-plane is a parabola. The axis of symmetry of the parabola passes through the vertex of the parabola. Therefore, the vertex of the parabola and the midpoint of the segment between the two $x$-intercepts of the graph have the same $x$-coordinate. Since $f(-3)=0$ and $f(-1)=0$, the $x$-coordinate of the vertex is $\frac{-3+(-1)}{2}=-2$. Of the shown intervals, only the interval in choice B contains $-2$.