SAT Question 7b17f86a: Linear Functions answer and explanation with Desmos solution

It's given that the function $f$ is defined by $f\left(x\right)=x+\frac{8}{11}$. Substituting $\frac{3}{11}$ for $x$ in the given function yields $f\left(\frac{3}{11}\right)=\frac{3}{11}+\frac{8}{11}$, which gives $f\left(\frac{3}{11}\right)=\frac{11}{11}$, or $f\left(\frac{3}{11}\right)=1$. Therefore, when $x=\frac{3}{11}$, the value of $f\left(x\right)$ is $1$.