SAT Question 7d5d1b32: Linear Equations In One Variable answer and explanation with Desmos solution

A linear equation in the form $ax+b=cx+d$ has no solution only when the coefficients of $x$ on each side of the equation are equal and the constant terms are not equal. Dividing both sides of the given equation by $2$ yields $kx-n=-\frac{28}{30}x-\frac{36}{38}$, or $kx-n=-\frac{14}{15}x-\frac{18}{19}$. Since it's given that the equation has no solution, the coefficient of $x$ on both sides of this equation must be equal, and the constant terms on both sides of this equation must not be equal. Since $\frac{18}{19}<1$, and it's given that $n>1$, the second condition is true. Thus, $k$ must be equal to $-\frac{14}{15}$. Note that -14/15, -.9333, and -0.933 are examples of ways to enter a correct answer.