SAT Question 7f87deff: Nonlinear Functions answer and explanation with Desmos solution

The x-intercepts of a graph in the xy-plane are the points at which the graph intersects the x-axis, or when the value of $y$ is $0$. Substituting $0$ for $y$ in the given equation yields $0=3\left(x-14\right)\left(x+5\right)\left(x+4\right)$. Dividing both sides of this equation by $3$ yields $0=\left(x-14\right)\left(x+5\right)\left(x+4\right)$. Applying the zero product property to this equation yields three equations: $x-14=0$, $x+5=0$, and $x+4=0$. Adding $14$ to both sides of the equation $x-14=0$ yields $x=14$, subtracting $5$ from both sides of the equation $x+5=0$ yields $x=-5$, and subtracting $4$ from both sides of the equation $x+4=0$ yields $x=-4$. Therefore, the x-coordinates of the x-intercepts of the graph of the given equation are $14$, $-5$, and $-4$. Note that 14, -5, and -4 are examples of ways to enter a correct answer.