SAT Question a049f400: Linear Inequalities answer and explanation with Desmos solution

Choice A is correct. Substituting $3$ for $x$ in the given inequality yields $y<5\left(3\right)+6$, or $y<21$. Therefore, when $x=3$, the corresponding value of $y$ is less than $21$. Substituting $5$ for $x$ in the given inequality yields $y<5\left(5\right)+6$, or $y<31$. Therefore, when $x=5$, the corresponding value of $y$ is less than $31$. Substituting $7$ for $x$ in the given inequality yields $y<5\left(7\right)+6$, or $y<41$. Therefore, when $x=7$, the corresponding value of $y$ is less than $41$. For the table in choice A, when $x=3$, the corresponding value of $y$ is $17$, which is less than $21$; when $x=5$, the corresponding value of $y$ is $27$, which is less than $31$; and when $x=7$, the corresponding value of $y$ is $37$, which is less than $41$. Therefore, the table in choice A gives values of $x$ and their corresponding values of $y$ that are all solutions to the given inequality.