Explanation
Correct answer: 1.1,11/10.
1h ( t ) = - 16 t^{2} + btb feet above the floor when it is released at . Substituting $19.36h ( t )0t, or $19.36 = b for in function yields . When the ball reaches the floor, its height is $0 for yields . Adding $16 t^{2}. Dividing both sides of this equation by $16t^{2} = 1.21t = 1.1 seconds after being released. Note that 1.1 and 11/10 are examples of ways to enter a correct answer.
Desmos solution:
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