SAT Question cbc4c163: Nonlinear Functions answer and explanation with Desmos solution

It’s given that the function $f$ is defined by $f\left(x\right)=5{\left(\frac{1}{4}-x\right)}^2+\frac{11}{4}$. Substituting $\frac{1}{4}$ for $x$ in this equation yields $f\left(\frac{1}{4}\right)=5{\left(\frac{1}{4}-\frac{1}{4}\right)}^2+\frac{11}{4}$, which is equivalent $f\left(\frac{1}{4}\right)=5{\left(0\right)}^2+\frac{11}{4}$, or $f\left(\frac{1}{4}\right)=\frac{11}{4}$. Therefore, the value of $f\left(\frac{1}{4}\right)$ is $\frac{11}{4}$. Note that 11/4, 2.75, and 2.750 are examples of ways to enter a correct answer.