SAT Question fbd5483f: Linear Inequalities answer and explanation with Desmos solution

Choice A is correct. It's given that the four odd integers are consecutive, ordered from least to greatest, and that the first odd integer is represented by $x$. It follows that the second odd integer is represented by $x+2$, the third odd integer is represented by $x+4$, and the fourth odd integer is represented by $x+6$. Therefore, the product of $12$ and the fourth odd integer is represented by $12\left(x+6\right)$, and $26$ less than the sum of the first and third odd integers is represented by $x+\left(x+4\right)-26$. Since the product of $12$ and the fourth odd integer is at most $26$ less than the sum of the first and third odd integers, it follows that $12\left(x+6\right)\le x+\left(x+4\right)-26$.