SAT Question 6dd463ca: Lines, Angles, and Triangles answer and explanation with Desmos solution

Choice B is correct. It's given that $\angle ACE$ measures $62^{\circ }$. Since segments $AE$ and $BD$ are parallel, $\angle BDC$ and $\angle CEA$ are congruent. Therefore, $\angle CEA$ measures $58^{\circ }$. The sum of the measures of $\angle ACE$, $\angle CEA$, and $\angle CAE$ is $180^{\circ }$ since the sum of the interior angles of triangle $ACE$ is equal to $180^{\circ }$. Let the measure of $\angle CAE$ be $x^{\circ }$. Therefore, $62+58+x=180$, which simplifies to $x=60$. Thus, the measure of $\angle CAE$ is $60^{\circ }$.